Classes/Class VII/Mathematics/Advanced Algebraic Expressions

Advanced Algebraic Expressions

Class VII Mathematics - Complex Algebra & Equations

4
MCQ Questions
4
Short Questions
2
Long Questions
90
Minutes
100
Max Marks
Question Type:
Difficulty:
MCQ
Easy
Question 1
What is the coefficient of x² in the expression 3x³ - 5x² + 2x - 7?
A. 3
B. -5
C. 2
D. -7

Answer:

The coefficient of x² is -5. In an algebraic expression, the coefficient is the numerical factor of a term. Here, -5 is multiplied by x².
MCQ
Easy
Question 2
Which of the following is a binomial?
A. 2x³ + 3x² - x + 5
B. x² + 3x
C. 7x
D. x³ + 2x² - x + 4 - 2

Answer:

x² + 3x is a binomial because it has exactly two terms. A binomial is an algebraic expression with two terms connected by + or - signs.
MCQ
Medium
Question 3
If x = 2, what is the value of 3x² - 4x + 1?
A. 5
B. 7
C. 9
D. 11

Answer:

Substituting x = 2: 3(2)² - 4(2) + 1 = 3(4) - 8 + 1 = 12 - 8 + 1 = 5.
MCQ
Medium
Question 4
What is the degree of the polynomial 5x⁴ - 3x² + 7x - 2?
A. 2
B. 3
C. 4
D. 5

Answer:

The degree of a polynomial is the highest power of the variable. Here, the highest power of x is 4, so the degree is 4.
SHORT
Easy
Question 5
Add the following algebraic expressions: (3x² + 2x - 5) + (x² - 4x + 3)

Answer:

To add algebraic expressions, we combine like terms: (3x² + 2x - 5) + (x² - 4x + 3) = 3x² + x² + 2x - 4x - 5 + 3 = 4x² - 2x - 2 Therefore, the sum is 4x² - 2x - 2.
SHORT
Medium
Question 6
Subtract (2x² - 3x + 1) from (5x² + x - 4)

Answer:

To subtract, we change the signs of the second expression and add: (5x² + x - 4) - (2x² - 3x + 1) = 5x² + x - 4 - 2x² + 3x - 1 = 5x² - 2x² + x + 3x - 4 - 1 = 3x² + 4x - 5 Therefore, the result is 3x² + 4x - 5.
SHORT
Medium
Question 7
Multiply: 3x(2x² - 4x + 5)

Answer:

Using the distributive property: 3x(2x² - 4x + 5) = 3x × 2x² - 3x × 4x + 3x × 5 = 6x³ - 12x² + 15x Therefore, the product is 6x³ - 12x² + 15x.
SHORT
Medium
Question 8
Factorize: x² + 7x + 12

Answer:

To factorize x² + 7x + 12, we need two numbers that multiply to 12 and add to 7. These numbers are 3 and 4 (since 3 × 4 = 12 and 3 + 4 = 7). Therefore: x² + 7x + 12 = (x + 3)(x + 4) Verification: (x + 3)(x + 4) = x² + 4x + 3x + 12 = x² + 7x + 12 ✓
LONG
Hard
Question 9
Solve the equation 3(x + 2) - 2(x - 1) = 15 and verify your answer.

Answer:

Step 1: Expand the brackets 3(x + 2) - 2(x - 1) = 15 3x + 6 - 2x + 2 = 15 Step 2: Combine like terms 3x - 2x + 6 + 2 = 15 x + 8 = 15 Step 3: Solve for x x = 15 - 8 x = 7 Step 4: Verification Substitute x = 7 in the original equation: LHS = 3(7 + 2) - 2(7 - 1) = 3(9) - 2(6) = 27 - 12 = 15 RHS = 15 Since LHS = RHS, our answer x = 7 is correct.
LONG
Hard
Question 10
A rectangular garden has length (2x + 3) meters and width (x - 1) meters. If the perimeter is 28 meters, find the value of x and the dimensions of the garden.

Answer:

Given information: - Length = (2x + 3) meters - Width = (x - 1) meters - Perimeter = 28 meters Step 1: Write the perimeter formula Perimeter = 2(Length + Width) 28 = 2[(2x + 3) + (x - 1)] Step 2: Simplify inside the brackets 28 = 2[2x + 3 + x - 1] 28 = 2[3x + 2] 28 = 6x + 4 Step 3: Solve for x 28 - 4 = 6x 24 = 6x x = 4 Step 4: Find the dimensions Length = 2x + 3 = 2(4) + 3 = 8 + 3 = 11 meters Width = x - 1 = 4 - 1 = 3 meters Step 5: Verification Perimeter = 2(11 + 3) = 2(14) = 28 meters ✓ Therefore, x = 4, length = 11 meters, and width = 3 meters.